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p=10/p
We move all terms to the left:
p-(10/p)=0
Domain of the equation: p)!=0We add all the numbers together, and all the variables
p!=0/1
p!=0
p∈R
p-(+10/p)=0
We get rid of parentheses
p-10/p=0
We multiply all the terms by the denominator
p*p-10=0
Wy multiply elements
p^2-10=0
a = 1; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·1·(-10)
Δ = 40
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{40}=\sqrt{4*10}=\sqrt{4}*\sqrt{10}=2\sqrt{10}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{10}}{2*1}=\frac{0-2\sqrt{10}}{2} =-\frac{2\sqrt{10}}{2} =-\sqrt{10} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{10}}{2*1}=\frac{0+2\sqrt{10}}{2} =\frac{2\sqrt{10}}{2} =\sqrt{10} $
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