q(1000-0.02q)=0

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Solution for q(1000-0.02q)=0 equation:



q(1000-0.02q)=0
We add all the numbers together, and all the variables
q(-0.02q+1000)=0
We multiply parentheses
0q^2+1000q=0
We add all the numbers together, and all the variables
q^2+1000q=0
a = 1; b = 1000; c = 0;
Δ = b2-4ac
Δ = 10002-4·1·0
Δ = 1000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1000000}=1000$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1000)-1000}{2*1}=\frac{-2000}{2} =-1000 $
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1000)+1000}{2*1}=\frac{0}{2} =0 $

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