q(1000-0.02q)=0

Solution for q(1000-0.02q)=0 equation:

q(1000-0.02q)=0

We add all the numbers together, and all the variables

q(-0.02q+1000)=0

We multiply parentheses

0q^2+1000q=0

We add all the numbers together, and all the variables

q^2+1000q=0

a = 1; b = 1000; c = 0;
Δ = b2-4ac
Δ = 10002-4·1·0
Δ = 1000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1000000}=1000$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1000)-1000}{2*1}=\frac{-2000}{2}
=-1000
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1000)+1000}{2*1}=\frac{0}{2}
=0
$