q(2-3q)=40

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Solution for q(2-3q)=40 equation: 



q(2-3q)=40

We move all terms to the left:

q(2-3q)-(40)=0

We add all the numbers together, and all the variables

q(-3q+2)-40=0

We multiply parentheses

-3q^2+2q-40=0

a = -3; b = 2; c = -40;
Δ = b2-4ac
Δ = 22-4·(-3)·(-40)
Δ = -476
Delta is less than zero, so there is no solution for the equation

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