q+2/5=(2q-11)/7

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Solution for q+2/5=(2q-11)/7 equation:



q+2/5=(2q-11)/7
We move all terms to the left:
q+2/5-((2q-11)/7)=0
We calculate fractions
q+(-((2q-11)*5)/()+()/()=0
We calculate terms in parentheses: +(-((2q-11)*5)/()+()/(), so:
-((2q-11)*5)/()+()/(
We add all the numbers together, and all the variables
-((2q-11)*5)/()+1
We multiply all the terms by the denominator
-((2q-11)*5)+1*()
We calculate terms in parentheses: -((2q-11)*5), so:
(2q-11)*5
We multiply parentheses
10q-55
Back to the equation:
-(10q-55)
We add all the numbers together, and all the variables
-(10q-55)
We get rid of parentheses
-10q+55
Back to the equation:
+(-10q+55)
We get rid of parentheses
q-10q+55=0
We add all the numbers together, and all the variables
-9q+55=0
We move all terms containing q to the left, all other terms to the right
-9q=-55
q=-55/-9
q=6+1/9

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