q+q=q*q

Solution for q+q=q*q equation:

q+q=q*q

We move all terms to the left:

q+q-(q*q)=0

We add all the numbers together, and all the variables

q+q-(+q*q)=0

We add all the numbers together, and all the variables

2q-(+q*q)=0

We get rid of parentheses

2q-q*q=0

Wy multiply elements

-1q^2+2q=0

a = -1; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-1)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-1}=\frac{-4}{-2}
=+2
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-1}=\frac{0}{-2}
=0
$