q+r(n-4)=d

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Solution for q+r(n-4)=d equation:


Simplifying
q + r(n + -4) = d

Reorder the terms:
q + r(-4 + n) = d
q + (-4 * r + n * r) = d

Reorder the terms:
q + (nr + -4r) = d
q + (nr + -4r) = d

Reorder the terms:
nr + q + -4r = d

Solving
nr + q + -4r = d

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-1q' to each side of the equation.
nr + q + -1q + -4r = d + -1q

Combine like terms: q + -1q = 0
nr + 0 + -4r = d + -1q
nr + -4r = d + -1q

Add '4r' to each side of the equation.
nr + -4r + 4r = d + -1q + 4r

Combine like terms: -4r + 4r = 0
nr + 0 = d + -1q + 4r
nr = d + -1q + 4r

Divide each side by 'r'.
n = dr-1 + -1qr-1 + 4

Simplifying
n = dr-1 + -1qr-1 + 4

Reorder the terms:
n = 4 + dr-1 + -1qr-1

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