q/3+3/4=(4q+9)/12

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Solution for q/3+3/4=(4q+9)/12 equation: 


q in (-oo:+oo)

q/3+3/4 = (4*q+9)/12 // - (4*q+9)/12

q/3-((4*q+9)/12)+3/4 = 0

(-1*(4*q+9))/12+q/3+3/4 = 0

(-1*3*4*(4*q+9))/(3*4*12)+(4*12*q)/(3*4*12)+(12*3^2)/(3*4*12) = 0

4*12*q-1*3*4*(4*q+9)+12*3^2 = 0

108-108 = 0

0 = 0

0/(3*4*12) = 0

0/(3*4*12) = 0 // * 3*4*12

0 = 0

q belongs to the empty set

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