q/9(q+8)-(3q-5)=21+11(-2q-13)

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Solution for q/9(q+8)-(3q-5)=21+11(-2q-13) equation: 



q/9(q+8)-(3q-5)=21+11(-2q-13)

We move all terms to the left:

q/9(q+8)-(3q-5)-(21+11(-2q-13))=0



Domain of the equation: 9(q+8)!=0

q∈R



We get rid of parentheses

q/9(q+8)-3q-(21+11(-2q-13))+5=0

We multiply all the terms by the denominator


q-3q*9(q+8)-((21+11(-2q-13)))*9(q+8)+5*9(q+8)=0



We calculate terms in parentheses: -((21+11(-2q-13)))*9(q+8), so:

(21+11(-2q-13)))*9(q+8



Wy multiply elements

-27q^2(q-((21+11(-2q-13)))*9(q+8)+45q(q+q=0

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