q2+17q=42

Solution for q2+17q=42 equation:

q2+17q=42

We move all terms to the left:

q2+17q-(42)=0

We add all the numbers together, and all the variables

q^2+17q-42=0

a = 1; b = 17; c = -42;
Δ = b2-4ac
Δ = 172-4·1·(-42)
Δ = 457
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{457}}{2*1}=\frac{-17-\sqrt{457}}{2}
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{457}}{2*1}=\frac{-17+\sqrt{457}}{2}
$