q2-26q=60

Solution for q2-26q=60 equation:

q2-26q=60

We move all terms to the left:

q2-26q-(60)=0

We add all the numbers together, and all the variables

q^2-26q-60=0

a = 1; b = -26; c = -60;
Δ = b2-4ac
Δ = -262-4·1·(-60)
Δ = 916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{916}=\sqrt{4*229}=\sqrt{4}*\sqrt{229}=2\sqrt{229}$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2\sqrt{229}}{2*1}=\frac{26-2\sqrt{229}}{2}
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2\sqrt{229}}{2*1}=\frac{26+2\sqrt{229}}{2}
$