q2-8q+9=0

Solution for q2-8q+9=0 equation:

q2-8q+9=0

We add all the numbers together, and all the variables

q^2-8q+9=0

a = 1; b = -8; c = +9;
Δ = b2-4ac
Δ = -82-4·1·9
Δ = 28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{28}=\sqrt{4*7}=\sqrt{4}*\sqrt{7}=2\sqrt{7}$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{7}}{2*1}=\frac{8-2\sqrt{7}}{2}
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{7}}{2*1}=\frac{8+2\sqrt{7}}{2}
$