If it's not what You are looking for type in the equation solver your own equation and let us solve it.
D( x )
2*k+4 = 0
2*k+4 = 0
2*k+4 = 0
2*k+4 = 0
x naleu017Cy do R
x belongs to the empty set
q = (10*k+9)/(2*k+4)+4
x belongs to the empty set
| 10x^2+16x+3=0 | | 20x+3.25=12.25 | | 10m-8-11m=-3+3 | | 2(n+8)=22 | | -6/5(x+10)+1/5x=-6 | | X+37+90+x+67=180 | | 1/5(-10k+75)=8+12k | | (x-5y)(x-5y)= | | (5x+8)+(-6x+2)= | | -5(5n-3)=30 | | -2x+20=4 | | 250-2x=10 | | 139.60/20 | | -4(4+r)=12 | | 5/4x+2=27 | | 28=-4(c-9) | | (2x+5)(2x+7)=0 | | 3y+4+6(1+y)=9y+10 | | -7/10t=9/8 | | 36=-9/5x | | 75x-x^2=1026 | | x-5/3=4/3 | | 3.8n-13=12d-2 | | x(6x+7)=20 | | 75x-x^2=900 | | 5-(m+3)=2(2m-4) | | 72+-17x+x^2=0 | | 3[2h-6]=2[2(3-h)-5] | | 4x-6=-24+7x | | 2[5-5(x-4)]=10-5x | | t=23b^13 | | y/4+8=12 |