r(2r-4)=(2r+1)(r-2)

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Solution for r(2r-4)=(2r+1)(r-2) equation: 



r(2r-4)=(2r+1)(r-2)

We move all terms to the left:

r(2r-4)-((2r+1)(r-2))=0

We multiply parentheses

2r^2-4r-((2r+1)(r-2))=0

We multiply parentheses ..

2r^2-((+2r^2-4r+r-2))-4r=0



We calculate terms in parentheses: -((+2r^2-4r+r-2)), so:

(+2r^2-4r+r-2)

We get rid of parentheses

2r^2-4r+r-2

We add all the numbers together, and all the variables

2r^2-3r-2

Back to the equation:

-(2r^2-3r-2)



We add all the numbers together, and all the variables

2r^2-4r-(2r^2-3r-2)=0

We get rid of parentheses

2r^2-2r^2-4r+3r+2=0

We add all the numbers together, and all the variables

-1r+2=0

We move all terms containing r to the left, all other terms to the right

-r=-2

r=-2/-1

r=+2

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