r(3r+2)=3r(1+r)+12

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Solution for r(3r+2)=3r(1+r)+12 equation: 


Simplifying
r(3r + 2) = 3r(1 + r) + 12

Reorder the terms:
r(2 + 3r) = 3r(1 + r) + 12
(2 * r + 3r * r) = 3r(1 + r) + 12
(2r + 3r2) = 3r(1 + r) + 12
2r + 3r2 = (1 * 3r + r * 3r) + 12
2r + 3r2 = (3r + 3r2) + 12

Reorder the terms:
2r + 3r2 = 12 + 3r + 3r2

Add '-3r2' to each side of the equation.
2r + 3r2 + -3r2 = 12 + 3r + 3r2 + -3r2

Combine like terms: 3r2 + -3r2 = 0
2r + 0 = 12 + 3r + 3r2 + -3r2
2r = 12 + 3r + 3r2 + -3r2

Combine like terms: 3r2 + -3r2 = 0
2r = 12 + 3r + 0
2r = 12 + 3r

Solving
2r = 12 + 3r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-3r' to each side of the equation.
2r + -3r = 12 + 3r + -3r

Combine like terms: 2r + -3r = -1r
-1r = 12 + 3r + -3r

Combine like terms: 3r + -3r = 0
-1r = 12 + 0
-1r = 12

Divide each side by '-1'.
r = -12

Simplifying
r = -12

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