r(r+2)+(r+2)=0

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Solution for r(r+2)+(r+2)=0 equation:


Simplifying
r(r + 2) + (r + 2) = 0

Reorder the terms:
r(2 + r) + (r + 2) = 0
(2 * r + r * r) + (r + 2) = 0
(2r + r2) + (r + 2) = 0

Reorder the terms:
2r + r2 + (2 + r) = 0

Remove parenthesis around (2 + r)
2r + r2 + 2 + r = 0

Reorder the terms:
2 + 2r + r + r2 = 0

Combine like terms: 2r + r = 3r
2 + 3r + r2 = 0

Solving
2 + 3r + r2 = 0

Solving for variable 'r'.

Factor a trinomial.
(2 + r)(1 + r) = 0

Subproblem 1

Set the factor '(2 + r)' equal to zero and attempt to solve: Simplifying 2 + r = 0 Solving 2 + r = 0 Move all terms containing r to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + r = 0 + -2 Combine like terms: 2 + -2 = 0 0 + r = 0 + -2 r = 0 + -2 Combine like terms: 0 + -2 = -2 r = -2 Simplifying r = -2

Subproblem 2

Set the factor '(1 + r)' equal to zero and attempt to solve: Simplifying 1 + r = 0 Solving 1 + r = 0 Move all terms containing r to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + r = 0 + -1 Combine like terms: 1 + -1 = 0 0 + r = 0 + -1 r = 0 + -1 Combine like terms: 0 + -1 = -1 r = -1 Simplifying r = -1

Solution

r = {-2, -1}

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