r(r-1)=(r-4)-6

Solution for r(r-1)=(r-4)-6 equation:

r(r-1)=(r-4)-6

We move all terms to the left:

r(r-1)-((r-4)-6)=0

We multiply parentheses

r^2-1r-((r-4)-6)=0


We calculate terms in parentheses: -((r-4)-6), so:

(r-4)-6

We get rid of parentheses

r-4-6

We add all the numbers together, and all the variables

r-10

Back to the equation:

-(r-10)


We get rid of parentheses

r^2-1r-r+10=0

We add all the numbers together, and all the variables

r^2-2r+10=0

a = 1; b = -2; c = +10;
Δ = b2-4ac
Δ = -22-4·1·10
Δ = -36
Delta is less than zero, so there is no solution for the equation