r(r-10)=0.r=

Solution for r(r-10)=0.r= equation:

r(r-10)=0.r=

We move all terms to the left:

r(r-10)-(0.r)=0

We add all the numbers together, and all the variables

r(r-10)-0=0

We add all the numbers together, and all the variables

r(r-10)=0

We multiply parentheses

r^2-10r=0

a = 1; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·1·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*1}=\frac{0}{2}
=0
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*1}=\frac{20}{2}
=10
$