r+(r-3)=(r+2)-(r+1)

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Solution for r+(r-3)=(r+2)-(r+1) equation:



r+(r-3)=(r+2)-(r+1)
We move all terms to the left:
r+(r-3)-((r+2)-(r+1))=0
We get rid of parentheses
r+r-((r+2)-(r+1))-3=0
We calculate terms in parentheses: -((r+2)-(r+1)), so:
(r+2)-(r+1)
We get rid of parentheses
r-r+2-1
We add all the numbers together, and all the variables
1
Back to the equation:
-(1)
We add all the numbers together, and all the variables
2r-4=0
We move all terms containing r to the left, all other terms to the right
2r=4
r=4/2
r=2

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