r+(r-3)=(r+2)-(r+1)

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Solution for r+(r-3)=(r+2)-(r+1) equation: 



r+(r-3)=(r+2)-(r+1)

We move all terms to the left:

r+(r-3)-((r+2)-(r+1))=0

We get rid of parentheses

r+r-((r+2)-(r+1))-3=0



We calculate terms in parentheses: -((r+2)-(r+1)), so:

(r+2)-(r+1)

We get rid of parentheses

r-r+2-1

We add all the numbers together, and all the variables

1

Back to the equation:

-(1)



We add all the numbers together, and all the variables

2r-4=0

We move all terms containing r to the left, all other terms to the right

2r=4

r=4/2

r=2

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