r+3=6(r+2)-5(r-5)

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Solution for r+3=6(r+2)-5(r-5) equation: 



r+3=6(r+2)-5(r-5)

We move all terms to the left:

r+3-(6(r+2)-5(r-5))=0



We calculate terms in parentheses: -(6(r+2)-5(r-5)), so:

6(r+2)-5(r-5)

We multiply parentheses

6r-5r+12+25

We add all the numbers together, and all the variables

r+37

Back to the equation:

-(r+37)



We get rid of parentheses

r-r-37+3=0

We add all the numbers together, and all the variables

-34!=0

There is no solution for this equation

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