r+7-4=-3(1+10r)-(r-6)

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Solution for r+7-4=-3(1+10r)-(r-6) equation: 



r+7-4=-3(1+10r)-(r-6)

We move all terms to the left:

r+7-4-(-3(1+10r)-(r-6))=0

We add all the numbers together, and all the variables

r-(-3(10r+1)-(r-6))+7-4=0

We add all the numbers together, and all the variables

r-(-3(10r+1)-(r-6))+3=0



We calculate terms in parentheses: -(-3(10r+1)-(r-6)), so:

-3(10r+1)-(r-6)

We multiply parentheses

-30r-(r-6)-3

We get rid of parentheses

-30r-r+6-3

We add all the numbers together, and all the variables

-31r+3

Back to the equation:

-(-31r+3)



We get rid of parentheses

r+31r-3+3=0

We add all the numbers together, and all the variables

32r=0

r=0/32

r=0

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