r-7+1-4r=-6(3-r)-2(4r-5)

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Solution for r-7+1-4r=-6(3-r)-2(4r-5) equation: 



r-7+1-4r=-6(3-r)-2(4r-5)

We move all terms to the left:

r-7+1-4r-(-6(3-r)-2(4r-5))=0

We add all the numbers together, and all the variables

r-4r-(-6(-1r+3)-2(4r-5))-7+1=0

We add all the numbers together, and all the variables

-3r-(-6(-1r+3)-2(4r-5))-6=0



We calculate terms in parentheses: -(-6(-1r+3)-2(4r-5)), so:

-6(-1r+3)-2(4r-5)

We multiply parentheses

6r-8r-18+10

We add all the numbers together, and all the variables

-2r-8

Back to the equation:

-(-2r-8)



We get rid of parentheses

-3r+2r+8-6=0

We add all the numbers together, and all the variables

-1r+2=0

We move all terms containing r to the left, all other terms to the right

-r=-2

r=-2/-1

r=+2

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