r/2(2-r)-r/4(3-2r)=r+10/6

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Solution for r/2(2-r)-r/4(3-2r)=r+10/6 equation: 


r in (-oo:+oo)

(r/2)*(2-r)-((r/4)*(3-(2*r))) = r+10/6 // - r+10/6

(r/2)*(2-r)-((r/4)*(3-(2*r)))-r-(10/6) = 0

(r/2)*(2-r)-((r/4)*(3-2*r))-r-5/3 = 0

1/2*r*(2-r)-1*1/4*r*(3-2*r)-r-5/3 = 0

(1/2*3*r*(2-r))/3+(-1*1/4*3*r*(3-2*r))/3+(3*(-r))/3-5/3 = 0

1/2*3*r*(2-r)-1*1/4*3*r*(3-2*r)+3*(-r)-5 = 0

3/4*r-3*r-5 = 0

-9/4*r-5 = 0

(-9/4*r-5)/3 = 0

(-9/4*r-5)/3 = 0 // * 3

-9/4*r-5 = 0

-9/4*r-5 = 0 // + 5

-9/4*r = 5 // : -9/4

r = 5/(-9/4)

r = -20/9

r = -20/9

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