r/4=(r+4)/7

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Solution for r/4=(r+4)/7 equation: 



r/4=(r+4)/7

We move all terms to the left:

r/4-((r+4)/7)=0

We calculate fractions


7r^2/()+(-((r+4)*4)/()=0



We calculate terms in parentheses: +(-((r+4)*4)/(), so:

-((r+4)*4)/(

We multiply all the terms by the denominator


-((r+4)*4)



We calculate terms in parentheses: -((r+4)*4), so:

(r+4)*4

We multiply parentheses

4r+16

Back to the equation:

-(4r+16)



We get rid of parentheses

-4r-16

Back to the equation:

+(-4r-16)



We get rid of parentheses

7r^2/()-4r-16=0

We multiply all the terms by the denominator


7r^2-4r*()-16*()=0

We add all the numbers together, and all the variables

7r^2-4r*()=0

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