r12/3;r=15/9

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Solution for r12/3;r=15/9 equation: 



r12/3r=15/9

We move all terms to the left:

r12/3r-(15/9)=0



Domain of the equation: 3r!=0

r!=0/3

r!=0

r∈R



We add all the numbers together, and all the variables

r12/3r-(+15/9)=0

We get rid of parentheses

r12/3r-15/9=0

We calculate fractions

We do not support erpression: r^12

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