If it's not what You are looking for type in the equation solver your own equation and let us solve it.
r2+10r=96
We move all terms to the left:
r2+10r-(96)=0
We add all the numbers together, and all the variables
r^2+10r-96=0
a = 1; b = 10; c = -96;
Δ = b2-4ac
Δ = 102-4·1·(-96)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-22}{2*1}=\frac{-32}{2} =-16 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+22}{2*1}=\frac{12}{2} =6 $
| X+3=3x-93 | | 3/4(4x+4)=4x+3 | | 82=10x+2 | | −4⋅36w=−1750 | | 15w+80=20w+70 | | x-1=5+32 | | 9z-64=z+32 | | -4=0.2x-9 | | 3x-1=2/(5x+33) | | y=0.2(-5)-9 | | -20-(-50)=x | | 9y+15+6y=180 | | -3+(1/2)x=(1/2)(-x+14) | | (x-2)(x+6)=9(20) | | x/6=15-7= | | -3+(1/2)n=(1/2)(-n+14) | | -5.4=0.2x-14.8 | | -20-(-50)=x|9 | | 5x2+7x-9=4x2+x-6 | | -12=0.5x-8 | | 9(2x-8)=-4(x-8) | | (1/2)n=(1/2)(-n+14) | | 10w-5=w+31 | | 2c-56=c | | -1(3-x)=-2x-5 | | -1(3-x)=-2x-9 | | 3z-92+z=180 | | y=1/2(4)-8 | | X/3+1+2x/3+2x=10 | | 3+2x=-4+x | | 42=32+n | | 3+2x=-4-x |