r2+12r+36=0

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Solution for r2+12r+36=0 equation: 



r2+12r+36=0

We add all the numbers together, and all the variables

r^2+12r+36=0

a = 1; b = 12; c = +36;
Δ = b2-4ac
Δ = 122-4·1·36
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$r=\frac{-b}{2a}=\frac{-12}{2}=-6$

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