r2-10r=-17

Solution for r2-10r=-17 equation:

r2-10r=-17

We move all terms to the left:

r2-10r-(-17)=0

We add all the numbers together, and all the variables

r^2-10r+17=0

a = 1; b = -10; c = +17;
Δ = b2-4ac
Δ = -102-4·1·17
Δ = 32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{32}=\sqrt{16*2}=\sqrt{16}*\sqrt{2}=4\sqrt{2}$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-4\sqrt{2}}{2*1}=\frac{10-4\sqrt{2}}{2}
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+4\sqrt{2}}{2*1}=\frac{10+4\sqrt{2}}{2}
$