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r2-30r+29=0
We add all the numbers together, and all the variables
r^2-30r+29=0
a = 1; b = -30; c = +29;
Δ = b2-4ac
Δ = -302-4·1·29
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-28}{2*1}=\frac{2}{2} =1 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+28}{2*1}=\frac{58}{2} =29 $
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