r2=0.0346/3.14

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Solution for r2=0.0346/3.14 equation:



r2=0.0346/3.14
We move all terms to the left:
r2-(0.0346/3.14)=0
We add all the numbers together, and all the variables
r2-(+0.0346/3.14)=0
We add all the numbers together, and all the variables
r^2-(+0.0346/3.14)=0
We get rid of parentheses
r^2-0.0346/3.14=0
We multiply all the terms by the denominator
r^2*3.14-0.0346=0
Wy multiply elements
3.14r^2-0.0346=0
a = 3.14; b = 0; c = -0.0346;
Δ = b2-4ac
Δ = 02-4·3.14·(-0.0346)
Δ = 0.434576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.434576}}{2*3.14}=\frac{0-\sqrt{0.434576}}{6.28} =-\frac{\sqrt{}}{6.28} $
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.434576}}{2*3.14}=\frac{0+\sqrt{0.434576}}{6.28} =\frac{\sqrt{}}{6.28} $

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