r=(0.2y-50)/40

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Solution for r=(0.2y-50)/40 equation: 


x in (-oo:+oo)

r = (0.2*y-50)/40 // - (0.2*y-50)/40

r-((0.2*y-50)/40) = 0

(-1*(0.2*y-50))/40+r = 0

(-1*(0.2*y-50))/40+(40*r)/40 = 0

40*r-1*(0.2*y-50) = 0

40*r-0.2*y+50 = 0

(40*r-0.2*y+50)/40 = 0

(40*r-0.2*y+50)/40 = 0 // * 40

40*r-0.2*y+50 = 0

x belongs to the empty set

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