r=(2/3)r

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Solution for r=(2/3)r equation: 



r=(2/3)r

We move all terms to the left:

r-((2/3)r)=0



Domain of the equation: 3)r)!=0

r!=0/1

r!=0

r∈R



We add all the numbers together, and all the variables

r-((+2/3)r)=0

We multiply all the terms by the denominator


r*3)r)-((+2=0

Wy multiply elements

3r^2+2=0

a = 3; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·3·2
Δ = -24
Delta is less than zero, so there is no solution for the equation

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