r=2(r-1)+5;r=2r+3

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Solution for r=2(r-1)+5;r=2r+3 equation:



r=2(r-1)+5r=2r+3
We move all terms to the left:
r-(2(r-1)+5r)=0
We calculate terms in parentheses: -(2(r-1)+5r), so:
2(r-1)+5r
We add all the numbers together, and all the variables
5r+2(r-1)
We multiply parentheses
5r+2r-2
We add all the numbers together, and all the variables
7r-2
Back to the equation:
-(7r-2)
We get rid of parentheses
r-7r+2=0
We add all the numbers together, and all the variables
-6r+2=0
We move all terms containing r to the left, all other terms to the right
-6r=-2
r=-2/-6
r=1/3

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