r=3(9r-3)+6

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Solution for r=3(9r-3)+6 equation: 



r=3(9r-3)+6

We move all terms to the left:

r-(3(9r-3)+6)=0



We calculate terms in parentheses: -(3(9r-3)+6), so:

3(9r-3)+6

We multiply parentheses

27r-9+6

We add all the numbers together, and all the variables

27r-3

Back to the equation:

-(27r-3)



We get rid of parentheses

r-27r+3=0

We add all the numbers together, and all the variables

-26r+3=0

We move all terms containing r to the left, all other terms to the right

-26r=-3

r=-3/-26

r=3/26

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