rt13/12=1

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Solution for rt13/12=1 equation: 


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m-(5*m)-(13/3)-(20/5) = 1

5;6;7;32

4*(1/2) = 0

2*x^(2/3)-(7*x^(1/3))-4 = 0

n/5-((9*n)/10) = 1/5

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