s+2(1/2)s+20=62

Solution for s+2(1/2)s+20=62 equation:

s+2(1/2)s+20=62

We move all terms to the left:

s+2(1/2)s+20-(62)=0


Domain of the equation: 2)s!=0

s!=0/1

s!=0

s∈R


We add all the numbers together, and all the variables

s+2(+1/2)s+20-62=0

We add all the numbers together, and all the variables

s+2(+1/2)s-42=0

We multiply parentheses

2s^2+s-42=0

a = 2; b = 1; c = -42;
Δ = b2-4ac
Δ = 12-4·2·(-42)
Δ = 337
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{337}}{2*2}=\frac{-1-\sqrt{337}}{4}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{337}}{2*2}=\frac{-1+\sqrt{337}}{4}
$