s+2(s+3)+(45-5)=48

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Solution for s+2(s+3)+(45-5)=48 equation: 



s+2(s+3)+(45-5)=48

We move all terms to the left:

s+2(s+3)+(45-5)-(48)=0

determiningTheFunctionDomain
s+2(s+3)-48+(45-5)=0

We add all the numbers together, and all the variables

s+2(s+3)-48+40=0

We add all the numbers together, and all the variables

s+2(s+3)-8=0

We multiply parentheses

s+2s+6-8=0

We add all the numbers together, and all the variables

3s-2=0

We move all terms containing s to the left, all other terms to the right

3s=2

s=2/3

s=2/3

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