s+2(s+3)+(4s-5)=148

Solution for s+2(s+3)+(4s-5)=148 equation:

Simplifying
s + 2(s + 3) + (4s + -5) = 148

Reorder the terms:
s + 2(3 + s) + (4s + -5) = 148
s + (3 * 2 + s * 2) + (4s + -5) = 148
s + (6 + 2s) + (4s + -5) = 148

Reorder the terms:
s + 6 + 2s + (-5 + 4s) = 148

Remove parenthesis around (-5 + 4s)
s + 6 + 2s + -5 + 4s = 148

Reorder the terms:
6 + -5 + s + 2s + 4s = 148

Combine like terms: 6 + -5 = 1
1 + s + 2s + 4s = 148

Combine like terms: s + 2s = 3s
1 + 3s + 4s = 148

Combine like terms: 3s + 4s = 7s
1 + 7s = 148

Solving
1 + 7s = 148

Solving for variable 's'.

Move all terms containing s to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 7s = 148 + -1

Combine like terms: 1 + -1 = 0
0 + 7s = 148 + -1
7s = 148 + -1

Combine like terms: 148 + -1 = 147
7s = 147

Divide each side by '7'.
s = 21

Simplifying
s = 21