s+2(s+3)=(4s-5)

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Solution for s+2(s+3)=(4s-5) equation: 



s+2(s+3)=(4s-5)

We move all terms to the left:

s+2(s+3)-((4s-5))=0

We multiply parentheses

s+2s-((4s-5))+6=0



We calculate terms in parentheses: -((4s-5)), so:

(4s-5)

We get rid of parentheses

4s-5

Back to the equation:

-(4s-5)



We add all the numbers together, and all the variables

3s-(4s-5)+6=0

We get rid of parentheses

3s-4s+5+6=0

We add all the numbers together, and all the variables

-1s+11=0

We move all terms containing s to the left, all other terms to the right

-s=-11

s=-11/-1

s=+11

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