s+21/2s+20=60

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Solution for s+21/2s+20=60 equation:



s+21/2s+20=60
We move all terms to the left:
s+21/2s+20-(60)=0
Domain of the equation: 2s!=0
s!=0/2
s!=0
s∈R
We add all the numbers together, and all the variables
s+21/2s-40=0
We multiply all the terms by the denominator
s*2s-40*2s+21=0
Wy multiply elements
2s^2-80s+21=0
a = 2; b = -80; c = +21;
Δ = b2-4ac
Δ = -802-4·2·21
Δ = 6232
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{6232}=\sqrt{4*1558}=\sqrt{4}*\sqrt{1558}=2\sqrt{1558}$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-2\sqrt{1558}}{2*2}=\frac{80-2\sqrt{1558}}{4} $
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+2\sqrt{1558}}{2*2}=\frac{80+2\sqrt{1558}}{4} $

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