s+3/12+20=47

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Solution for s+3/12+20=47 equation: 



s+3/12+20=47

We move all terms to the left:

s+3/12+20-(47)=0

determiningTheFunctionDomain
s+20-47+3/12=0

We add all the numbers together, and all the variables

s-27+3/12=0

We multiply all the terms by the denominator


s*12+3-27*12=0

We add all the numbers together, and all the variables

s*12-321=0

Wy multiply elements

12s-321=0

We move all terms containing s to the left, all other terms to the right

12s=321

s=321/12

s=26+3/4

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