s+7/2s+10=64

Solution for s+7/2s+10=64 equation:

s+7/2s+10=64

We move all terms to the left:

s+7/2s+10-(64)=0


Domain of the equation: 2s!=0

s!=0/2

s!=0

s∈R


We add all the numbers together, and all the variables

s+7/2s-54=0

We multiply all the terms by the denominator


s*2s-54*2s+7=0

Wy multiply elements

2s^2-108s+7=0

a = 2; b = -108; c = +7;
Δ = b2-4ac
Δ = -1082-4·2·7
Δ = 11608
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11608}=\sqrt{4*2902}=\sqrt{4}*\sqrt{2902}=2\sqrt{2902}$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-108)-2\sqrt{2902}}{2*2}=\frac{108-2\sqrt{2902}}{4}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-108)+2\sqrt{2902}}{2*2}=\frac{108+2\sqrt{2902}}{4}
$