s+s+2=3(s+4)+7

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Solution for s+s+2=3(s+4)+7 equation: 



s+s+2=3(s+4)+7

We move all terms to the left:

s+s+2-(3(s+4)+7)=0

We add all the numbers together, and all the variables

2s-(3(s+4)+7)+2=0



We calculate terms in parentheses: -(3(s+4)+7), so:

3(s+4)+7

We multiply parentheses

3s+12+7

We add all the numbers together, and all the variables

3s+19

Back to the equation:

-(3s+19)



We get rid of parentheses

2s-3s-19+2=0

We add all the numbers together, and all the variables

-1s-17=0

We move all terms containing s to the left, all other terms to the right

-s=17

s=17/-1

s=-17

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