s-(n-4)=3(n+2)

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Solution for s-(n-4)=3(n+2) equation:


Simplifying
s + -1(n + -4) = 3(n + 2)

Reorder the terms:
s + -1(-4 + n) = 3(n + 2)
s + (-4 * -1 + n * -1) = 3(n + 2)
s + (4 + -1n) = 3(n + 2)

Reorder the terms:
4 + -1n + s = 3(n + 2)

Reorder the terms:
4 + -1n + s = 3(2 + n)
4 + -1n + s = (2 * 3 + n * 3)
4 + -1n + s = (6 + 3n)

Solving
4 + -1n + s = 6 + 3n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-3n' to each side of the equation.
4 + -1n + -3n + s = 6 + 3n + -3n

Combine like terms: -1n + -3n = -4n
4 + -4n + s = 6 + 3n + -3n

Combine like terms: 3n + -3n = 0
4 + -4n + s = 6 + 0
4 + -4n + s = 6

Add '-4' to each side of the equation.
4 + -4n + -4 + s = 6 + -4

Reorder the terms:
4 + -4 + -4n + s = 6 + -4

Combine like terms: 4 + -4 = 0
0 + -4n + s = 6 + -4
-4n + s = 6 + -4

Combine like terms: 6 + -4 = 2
-4n + s = 2

Add '-1s' to each side of the equation.
-4n + s + -1s = 2 + -1s

Combine like terms: s + -1s = 0
-4n + 0 = 2 + -1s
-4n = 2 + -1s

Divide each side by '-4'.
n = -0.5 + 0.25s

Simplifying
n = -0.5 + 0.25s

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