s-3/s+1=5/3

Solution for s-3/s+1=5/3 equation:

D( s )

s = 0

s = 0

s = 0

s in (-oo:0) U (0:+oo)

s-(3/s)+1 = 5/3 // - 5/3

s-(3/s)-(5/3)+1 = 0

s-3*s^-1-5/3+1 = 0

1*s^1-3*s^-1-2/3*s^0 = 0

(1*s^2-2/3*s^1-3*s^0)/(s^1) = 0 // * s^2

s^1*(1*s^2-2/3*s^1-3*s^0) = 0

s^1

s^2+(-2/3)*s-3 = 0

s^2+(-2/3)*s-3 = 0

DELTA = (-2/3)^2-(-3*1*4)

DELTA = 112/9

DELTA > 0

s = ((112/9)^(1/2)-(-2/3))/(1*2) or s = (-(-2/3)-(112/9)^(1/2))/(1*2)

s = ((112/9)^(1/2)+2/3)/2 or s = (2/3-(112/9)^(1/2))/2

s in { (2/3-(112/9)^(1/2))/2, ((112/9)^(1/2)+2/3)/2} 

s in { (2/3-(112/9)^(1/2))/2, ((112/9)^(1/2)+2/3)/2 }