s=3(-4/7)

Solution for s=3(-4/7) equation:

s=3(-4/7)

We move all terms to the left:

s-(3(-4/7))=0

We multiply all the terms by the denominator


s*7))-(3(-4=0

Wy multiply elements

7s^2-4=0

a = 7; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·7·(-4)
Δ = 112
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{112}=\sqrt{16*7}=\sqrt{16}*\sqrt{7}=4\sqrt{7}$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{7}}{2*7}=\frac{0-4\sqrt{7}}{14}
=-\frac{4\sqrt{7}}{14}
=-\frac{2\sqrt{7}}{7}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{7}}{2*7}=\frac{0+4\sqrt{7}}{14}
=\frac{4\sqrt{7}}{14}
=\frac{2\sqrt{7}}{7}
$