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x in (-oo:+oo)
s = ((3*(r-2))/5)*(r+2) // - ((3*(r-2))/5)*(r+2)
s-(((3*(r-2))/5)*(r+2)) = 0
(-3/5)*(r+2)*(r-2)+s = 0
s-3/5*(r+2)*(r-2) = 0
s-3/5*(r+2)*(r-2) = 0
s-3/5*r^2+12/5 = 0
s-3/5*r^2+12/5 = 0
x belongs to the empty set
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