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s=3,8s2=

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Solution for s=3,8s2= equation:



s=3.8s^2=
We move all terms to the left:
s-(3.8s^2)=0
We get rid of parentheses
-3.8s^2+s=0
a = -3.8; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-3.8)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
s_{1}=\frac{-b-\sqrt{\Delta}}{2a}
s_{2}=\frac{-b+\sqrt{\Delta}}{2a}

\sqrt{\Delta}=\sqrt{1}=1
s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-3.8}=\frac{-2}{-7.6} =2/7.6
s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-3.8}=\frac{0}{-7.6} =0

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