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s=7.6s^2
We move all terms to the left:
s-(7.6s^2)=0
We get rid of parentheses
-7.6s^2+s=0
a = -7.6; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-7.6)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-7.6}=\frac{-2}{-15.2} =2/15.2 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-7.6}=\frac{0}{-15.2} =0 $
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