s=n/2(a+b)

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Solution for s=n/2(a+b) equation: 


x in (-oo:+oo)

s = (n/2)*(a+b) // - (n/2)*(a+b)

s-((n/2)*(a+b)) = 0

s-1*1/2*n*(a+b) = 0

s-1*1/2*n*(a+b) = 0

s-1/2*a*n-1/2*b*n = 0

s-1/2*a*n-1/2*b*n = 0

x belongs to the empty set

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