sin(12/n)

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Solution for sin(12/n) equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

sin(12/n) = 0

sin(12/n) = 0  <=>  12/n = pi*k_1 i k_1 należy do I

t_1 = pi*k_1

12/n-t_1 = 0

12*n^-1 = t_1 // : 12

n^-1 = t_1/12

-1 < 0

1/(n^1) = t_1/12 // * n^1

1 = n^1*(t_1/12) // : t_1/12

12*t_1^-1 = n^1

n = 12*t_1^-1

n = 12*pi*k_1^-1 i k_1 należy do I

n = 12*pi*k_1^-1

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